What is the integral from 0 to 2 of e^t ?

The integral from 0 to 2 of e^t is e^2-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of e^t

\int_{0}^{2} e^{t} d t

e^{2} - 1

Decimal Notation

6.38905 \dots

Solution steps

\int_{0}^{2} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= [e^{t}]_{0}^{2}

Compute the boundaries:

e^{2} - 1

= e^{2} - 1

\int_{- 5}^{0} 2 + 25 - x^{2} d x

\int_{0}^{x c o s (x)} 25 - t^{2} d t

\int_{0}^{4} x^{2} - 4 d x

\int_{2}^{5} 3^{5 x} d x

\int_{- 2}^{- 1} \frac{1}{x ^{2}} d x

What is the integral from 0 to 2 of e^t ?
The integral from 0 to 2 of e^t is e^2-1