What is the integral from 0 to 4 of sin(x) ?

The integral from 0 to 4 of sin(x) is -cos(4)+1

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integral from 0 to 4 of sin(x)

\int_{0}^{4} sin (x) d x

- cos (4) + 1

Decimal Notation

1.65364 \dots

Solution steps

\int_{0}^{4} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{4}

Compute the boundaries:

- cos (4) + 1

= - cos (4) + 1

\int_{0}^{3} (2 x) d x

\int_{0}^{2} (1 - x^{2}) d x

\int_{1}^{\infty} 8 x^{- 9} d x

\int_{1}^{2} \frac{1}{x ^{2} - 3 x + 2} d x

\int_{0}^{1} x^{2} - 2 x d x

What is the integral from 0 to 4 of sin(x) ?
The integral from 0 to 4 of sin(x) is -cos(4)+1