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Popular >

integral from 1 to 3 of 6-2x

Solution

\int_{1}^{3} 6 - 2 x d x

Solution

4

Solution steps

\int_{1}^{3} 6 - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 6 d x - \int_{1}^{3} 2 x d x

\int_{1}^{3} 6 d x = 12

\int_{1}^{3} 2 x d x = 8

= 12 - 8

Simplify

= 4

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\int_{0}^{4} 4 x d x

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\int_{\frac{- π}{2}}^{\frac{π}{2}} sin (x) d x

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\int_{0}^{2} 2 sin (\frac{nπ x}{2}) d x

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\int_{0}^{4} \frac{1}{1 + u} d u

integral from 3 to x of (sin(t))/t

\int_{3}^{x} \frac{sin ( t )}{t} d t

Frequently Asked Questions (FAQ)

What is the integral from 1 to 3 of 6-2x ?
The integral from 1 to 3 of 6-2x is 4