What is the integral from 1 to 3 of (2-3/(x^2)) ?

The integral from 1 to 3 of (2-3/(x^2)) is 2

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integral from 1 to 3 of (2-3/(x^2))

\int_{1}^{3} (2 - \frac{3}{x ^{2}}) d x

2

Solution steps

\int_{1}^{3} 2 - \frac{3}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 2 d x - \int_{1}^{3} \frac{3}{x ^{2}} d x

\int_{1}^{3} 2 d x = 4

\int_{1}^{3} \frac{3}{x ^{2}} d x = 2

= 4 - 2

Simplify

= 2

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What is the integral from 1 to 3 of (2-3/(x^2)) ?
The integral from 1 to 3 of (2-3/(x^2)) is 2