What is the integral from 0 to 6 of g(x) ?

The integral from 0 to 6 of g(x) is g*18

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integral from 0 to 6 of g(x)

\int_{0}^{6} g (x) d x

g \cdot 18

Solution steps

\int_{0}^{6} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{0}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{6}

= g [\frac{x ^{2}}{2}]_{0}^{6}

Compute the boundaries:

18

= g \cdot 18

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What is the integral from 0 to 6 of g(x) ?
The integral from 0 to 6 of g(x) is g*18