What is the integral from-1 to 0 of x^{1/3}-x ?

The integral from-1 to 0 of x^{1/3}-x is -1/4

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integral from-1 to 0 of x^{1/3}-x

\int_{- 1}^{0} x^{\frac{1}{3}} - x d x

- \frac{1}{4}

Decimal Notation

- 0.25

Solution steps

\int_{- 1}^{0} x^{\frac{1}{3}} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} x^{\frac{1}{3}} d x - \int_{- 1}^{0} x d x

\int_{- 1}^{0} x^{\frac{1}{3}} d x = \frac{3 ( - 1 ) ^{\frac{1}{3}}}{4}

\int_{- 1}^{0} x d x = - \frac{1}{2}

= \frac{3 ( - 1 ) ^{\frac{1}{3}}}{4} - (- \frac{1}{2})

Simplify

\frac{3 ( - 1 ) ^{\frac{1}{3}}}{4} - (- \frac{1}{2}) : - \frac{1}{4}

= - \frac{1}{4}

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What is the integral from-1 to 0 of x^{1/3}-x ?
The integral from-1 to 0 of x^{1/3}-x is -1/4