What is the integral from-1 to 0 of x^{2/5} ?

The integral from-1 to 0 of x^{2/5} is (5(-1)^{2/5})/7

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integral from-1 to 0 of x^{2/5}

\int_{- 1}^{0} x^{\frac{2}{5}} d x

\frac{5 ( - 1 ) ^{\frac{2}{5}}}{7}

Solution steps

\int_{- 1}^{0} x^{\frac{2}{5}} d x

Apply the Power Rule

: [\frac{5}{7} x^{\frac{7}{5}}]_{- 1}^{0}

= [\frac{5}{7} x^{\frac{7}{5}}]_{- 1}^{0}

Compute the boundaries:

(- 1)^{\frac{2}{5}} \frac{5}{7}

= (- 1)^{\frac{2}{5}} \frac{5}{7}

Simplify

= \frac{5 ( - 1 ) ^{\frac{2}{5}}}{7}

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What is the integral from-1 to 0 of x^{2/5} ?
The integral from-1 to 0 of x^{2/5} is (5(-1)^{2/5})/7