What is the integral from 6x to-8 of sin(t^2) ?

The integral from 6x to-8 of sin(t^2) is sqrt(pi/2)\S(-8sqrt(2/pi))-sqrt(pi/2)\S(sqrt(2/pi)*6x)

Popular >

integral from 6x to-8 of sin(t^2)

\int_{6 x}^{- 8} sin (t^{2}) d t

\frac{π}{2} § (- 8 \frac{2}{π}) - \frac{π}{2} § (\frac{2}{π} \cdot 6 x)

Solution steps

\int_{6 x}^{- 8} sin (t^{2}) d t

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} t)]_{6 x}^{- 8}

Compute the boundaries:

\frac{π}{2} § (- 8 \frac{2}{π}) - \frac{π}{2} § (\frac{2}{π} \cdot 6 x)

= \frac{π}{2} § (- 8 \frac{2}{π}) - \frac{π}{2} § (\frac{2}{π} \cdot 6 x)

\int_{1}^{e} \frac{( 2 + ln ( x ) ) ^{3}}{x} d x

\int_{- 1}^{0} (- x - 1) d x

\int_{1}^{e^{x}} \frac{1}{t} d t

\int_{0}^{\frac{x}{n}} n (1 - x)^{n - 1} d x

\int_{0}^{\frac{π}{2}} x cos (n x) d x

What is the integral from 6x to-8 of sin(t^2) ?
The integral from 6x to-8 of sin(t^2) is sqrt(pi/2)\S(-8sqrt(2/pi))-sqrt(pi/2)\S(sqrt(2/pi)*6x)