What is the integral from 5 to infinity of 1/x ?

The integral from 5 to infinity of 1/x is diverges

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integral from 5 to infinity of 1/x

\int_{5}^{\infty} \frac{1}{x} d x

diverges

Solution steps

\int_{5}^{\infty} \frac{1}{x} d x

Compute the indefinite integral:

\int \frac{1}{x} d x = ln ∣ x ∣ + C

Compute the boundaries:

\int_{5}^{\infty} \frac{1}{x} d x =

diverges

= diverges

\int_{0}^{2} (2 x^{3} + 3) d x

\int_{0}^{1} x (1 - x)^{3} d x

\int_{0}^{4} \frac{1}{x - 2} d x

\int_{3}^{\infty} \frac{1}{x ^{5}} d x

\int_{0}^{1} e^{t x} 2 x d x

What is the integral from 5 to infinity of 1/x ?
The integral from 5 to infinity of 1/x is diverges