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Popular >

xy^'+5y=x^3-x

Solution

x y^{^{'}} + 5 y = x^{3} - x

Solution

y = \frac{x ^{3}}{8} - \frac{x}{6} + \frac{c _{1}}{x ^{5}}

Solution steps

x y^{'} (x) + 5 y = x^{3} - x

Solve linear ODE:

y = \frac{x ^{3}}{8} - \frac{x}{6} + \frac{c _{1}}{x ^{5}}

y = \frac{x ^{3}}{8} - \frac{x}{6} + \frac{c _{1}}{x ^{5}}

Popular Examples

integral of (x+1)/(x^2-2x)

\int \frac{x + 1}{x ^{2} - 2 x} d x

(\partial)/(\partial s)(s*cos(t))

\frac{\partial}{\partial s} (s \cdot cos (t))

f (x) = 6 cos (2 x)

derivative of f(x)=(x^3-8)/(x^2+3)derivative of

f (x) = \frac{x ^{3} - 8}{x ^{2} + 3}

tangent of f(x)=3x^2+2x-10,\at x=1 tangent of

f (x) = 3 x^{2} + 2 x - 10, at x = 1

Frequently Asked Questions (FAQ)

What is the solution for xy^'+5y=x^3-x ?
The solution for xy^'+5y=x^3-x is y=(x^3)/8-x/6+(c_{1})/(x^5)