What is the integral from 0 to 5 of 1/(1-x^2) ?

The integral from 0 to 5 of 1/(1-x^2) is diverges

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integral from 0 to 5 of 1/(1-x^2)

\int_{0}^{5} \frac{1}{1 - x ^{2}} d x

diverges

Solution steps

\int_{0}^{5} \frac{1}{1 - x ^{2}} d x

Find undefined (singularity) points:

x = 1

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{1} \frac{1}{1 - x ^{2}} d x + \int_{1}^{5} \frac{1}{1 - x ^{2}} d x

\int_{0}^{1} \frac{1}{1 - x ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{\frac{1}{2}} x arctan (2 x) d x

\int_{2}^{5} ln (x) + sin (x) + 8 d x

\int_{\frac{y}{n}}^{1} n (1 - x)^{n - 1} d x

\int_{1}^{3} (x^{2} - 8 x + 15) d x

What is the integral from 0 to 5 of 1/(1-x^2) ?
The integral from 0 to 5 of 1/(1-x^2) is diverges