What is the integral from-1 to 1 of 4x^2 ?

The integral from-1 to 1 of 4x^2 is 8/3

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integral from-1 to 1 of 4x^2

\int_{- 1}^{1} 4 x^{2} d x

\frac{8}{3}

Solution steps

\int_{- 1}^{1} 4 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{1}

= 4 [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= 4 \cdot \frac{2}{3}

Simplify

= \frac{8}{3}

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What is the integral from-1 to 1 of 4x^2 ?
The integral from-1 to 1 of 4x^2 is 8/3