What is the integral from-1 to 1 of t^7(1+t^8)^7 ?

The integral from-1 to 1 of t^7(1+t^8)^7 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of t^7(1+t^8)^7

\int_{- 1}^{1} t^{7} (1 + t^{8})^{7} d t

0

Solution steps

\int_{- 1}^{1} t^{7} (1 + t^{8})^{7} d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

t^{7} (1 + t^{8})^{7} :

Odd

= 0

\int_{0}^{1} x arctan (x^{2}) d x

\int_{0}^{1} - x^{2} + 2 x d x

\int_{- 1}^{1} \frac{3 x ^{2}}{2} d x

\int_{0}^{l n (2 x)} sin (6 e^{t}) d t

\int_{0}^{1} 8 t i + t j - k d t

What is the integral from-1 to 1 of t^7(1+t^8)^7 ?
The integral from-1 to 1 of t^7(1+t^8)^7 is 0