What is the integral from 0 to 4 of (2t^2+t^{3/2}) ?

The integral from 0 to 4 of (2t^2+t^{3/2}) is 832/15

Popular >

integral from 0 to 4 of (2t^2+t^{3/2})

\int_{0}^{4} (2 t^{2} + t^{\frac{3}{2}}) d t

\frac{832}{15}

Solution steps

\int_{0}^{4} 2 t^{2} + t^{\frac{3}{2}} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 t^{2} d t + \int_{0}^{4} t^{\frac{3}{2}} d t

\int_{0}^{4} 2 t^{2} d t = \frac{128}{3}

\int_{0}^{4} t^{\frac{3}{2}} d t = \frac{64}{5}

= \frac{128}{3} + \frac{64}{5}

Simplify

\frac{128}{3} + \frac{64}{5} : \frac{832}{15}

= \frac{832}{15}

\int_{0}^{1} 1 + 6 x^{\frac{3}{2}} d x

\int_{0}^{25} 2 x d x

\int_{0}^{2} (\frac{x ^{2} - 2}{x + 1}) d x

\int_{1}^{4} x^{- \frac{1}{2}} d x

\int_{0}^{4} (y - 2) (2 y + 1) d y

What is the integral from 0 to 4 of (2t^2+t^{3/2}) ?
The integral from 0 to 4 of (2t^2+t^{3/2}) is 832/15