What is the integral from 1 to 4 of x^{-1/2} ?

The integral from 1 to 4 of x^{-1/2} is 2

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integral from 1 to 4 of x^{-1/2}

\int_{1}^{4} x^{- \frac{1}{2}} d x

2

Solution steps

\int_{1}^{4} x^{- \frac{1}{2}} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{4}

= [2 x^{\frac{1}{2}}]_{1}^{4}

Compute the boundaries:

2

= 2

\int_{0}^{4} (y - 2) (2 y + 1) d y

\int_{0}^{3} (3 x - 8) d x

\int_{3}^{4} x^{4} d x

\int_{1}^{2} (2 x + \frac{1}{x}) d x

\int_{0}^{2} 3^{3 x} d x

What is the integral from 1 to 4 of x^{-1/2} ?
The integral from 1 to 4 of x^{-1/2} is 2