What is the integral from 0 to x of x^3 ?

The integral from 0 to x of x^3 is (x^4)/4

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integral from 0 to x of x^3

\int_{0}^{x} x^{3} d x

\frac{x ^{4}}{4}

Solution steps

\int_{0}^{x} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{x}

= [\frac{x ^{4}}{4}]_{0}^{x}

Compute the boundaries:

\frac{x ^{4}}{4}

= \frac{x ^{4}}{4}

\int_{c o s (x)}^{1} 1 - t^{2} d t

\int_{0}^{4} \frac{1}{x + 3} d x

\int_{0}^{1} - 6 x^{3} (3 x^{4} - 2)^{5} d x

\int_{0}^{1} \frac{1}{3 + e ^{- 2 x}} d x

\int_{0}^{5} x^{2} - 9 d x

What is the integral from 0 to x of x^3 ?
The integral from 0 to x of x^3 is (x^4)/4