What is the integral from 6 to 9 of 1/(x^2) ?

The integral from 6 to 9 of 1/(x^2) is 1/18

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integral from 6 to 9 of 1/(x^2)

\int_{6}^{9} \frac{1}{x ^{2}} d x

\frac{1}{18}

Solution steps

\int_{6}^{9} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{6}^{9}

= [- \frac{1}{x}]_{6}^{9}

Compute the boundaries:

\frac{1}{18}

= \frac{1}{18}

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What is the integral from 6 to 9 of 1/(x^2) ?
The integral from 6 to 9 of 1/(x^2) is 1/18