What is the integral from 3 to 7 of 1/(x^2) ?

The integral from 3 to 7 of 1/(x^2) is 4/21

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integral from 3 to 7 of 1/(x^2)

\int_{3}^{7} \frac{1}{x ^{2}} d x

\frac{4}{21}

Decimal

0.19047 \dots

Solution steps

\int_{3}^{7} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{3}^{7}

= [- \frac{1}{x}]_{3}^{7}

Compute the boundaries:

\frac{4}{21}

= \frac{4}{21}

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\int_{1}^{4} 1 + \frac{1}{x} + \frac{1}{x ^{2}} d x

\int_{0}^{1} x^{2} y d x

What is the integral from 3 to 7 of 1/(x^2) ?
The integral from 3 to 7 of 1/(x^2) is 4/21