What is the integral from 0 to 1 of 1/(x^6) ?

The integral from 0 to 1 of 1/(x^6) is diverges

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integral from 0 to 1 of 1/(x^6)

\int_{0}^{1} \frac{1}{x ^{6}} d x

diverges

Solution steps

\int_{0}^{1} \frac{1}{x ^{6}} d x

Apply the Power Rule

: [- \frac{1}{5 x ^{5}}]_{0}^{1}

= [- \frac{1}{5 x ^{5}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int_{0}^{l} x d x

\int_{1}^{l n (5)} e^{2 x + y} d y

\int_{- \frac{π}{2}}^{\frac{π}{2}} 4 cos (x) d x

\int_{0}^{π} sin (φ) d φ

\int_{1}^{6} (x + 1) (x^{2} + 2 x)^{2} d x

What is the integral from 0 to 1 of 1/(x^6) ?
The integral from 0 to 1 of 1/(x^6) is diverges