What is the integral from 0 to pi/2 of 1/(1-cos(x)) ?

The integral from 0 to pi/2 of 1/(1-cos(x)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/2 of 1/(1-cos(x))

\int_{0}^{\frac{π}{2}} \frac{1}{1 - cos ( x )} d x

diverges

Solution steps

\int_{0}^{\frac{π}{2}} \frac{1}{1 - cos ( x )} d x

Apply u-substitution

: \int_{0}^{1} \frac{1}{u ^{2}} d u

= \int_{0}^{1} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{0}^{1}

= [- \frac{1}{u}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int_{- 1}^{2} 3 x^{2} + 8 x d x

\int_{1}^{10} \frac{20}{x ^{2}} d x

\int_{0}^{2 π} - cos^{2} (t) d t

\int_{1}^{10} \frac{7}{x} d x

\int_{0}^{1} (\frac{1}{x + 1}) d x

What is the integral from 0 to pi/2 of 1/(1-cos(x)) ?
The integral from 0 to pi/2 of 1/(1-cos(x)) is diverges