What is the integral from-1 to 3 of 1/((x+2)^2) ?

The integral from-1 to 3 of 1/((x+2)^2) is 4/5

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integral from-1 to 3 of 1/((x+2)^2)

\int_{- 1}^{3} \frac{1}{( x + 2 ) ^{2}} d x

\frac{4}{5}

Decimal

0.8

Solution steps

\int_{- 1}^{3} \frac{1}{( x + 2 ) ^{2}} d x

Apply u-substitution

: \int_{1}^{5} \frac{1}{u ^{2}} d u

= \int_{1}^{5} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{1}^{5}

= [- \frac{1}{u}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= \frac{4}{5}

\int_{\frac{1}{2}}^{2} (6 - \frac{6}{x ^{2}}) d x

\int_{- 4}^{4} \frac{x}{2} + 1 d x

\int_{- 1}^{1} x (x - 2) d x

\int_{0}^{3} 2 x^{3} d x

\int_{0}^{r} \frac{1}{r ^{2}} d r

What is the integral from-1 to 3 of 1/((x+2)^2) ?
The integral from-1 to 3 of 1/((x+2)^2) is 4/5