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Popular >

integral from-1 to 1 of (8x-2)

Solution

\int_{- 1}^{1} (8 x - 2) d x

Solution

- 4

Solution steps

\int_{- 1}^{1} 8 x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 8 x d x - \int_{- 1}^{1} 2 d x

\int_{- 1}^{1} 8 x d x = 0

\int_{- 1}^{1} 2 d x = 4

= 0 - 4

Simplify

= - 4

Graph

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\int_{0}^{1} sec (x) d x

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\int_{0}^{4} x 9 + x^{2} d x

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\int_{1}^{e} \frac{ln ^{4} ( x )}{x} d x

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\int_{- 1}^{7} x - 4 x^{2} d x

integral from-infinity to 3 of e^{|x+1|}

\int_{- \infty}^{3} e^{∣ x + 1 ∣} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (8x-2) ?
The integral from-1 to 1 of (8x-2) is -4