What is the integral from 1 to 3 of sin(x) ?

The integral from 1 to 3 of sin(x) is -cos(3)+cos(1)

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integral from 1 to 3 of sin(x)

\int_{1}^{3} sin (x) d x

- cos (3) + cos (1)

Decimal

1.53029 \dots

Solution steps

\int_{1}^{3} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{1}^{3}

Compute the boundaries:

- cos (3) + cos (1)

= - cos (3) + cos (1)

\int_{1}^{2} (2 x + 1) d x

\int_{x}^{2} sin (t^{2}) d t

\int_{1}^{2} 12 (y - 1) x^{3} e^{2 x (y - 1)} d y

\int_{0}^{x} \frac{1}{3} e^{- \frac{1}{3} t} d t

\int_{- 2}^{1} (x^{2} - 1) d x

What is the integral from 1 to 3 of sin(x) ?
The integral from 1 to 3 of sin(x) is -cos(3)+cos(1)