What is the integral from 0 to 2 of 2pi(7-x)(8-x^3) ?

The integral from 0 to 2 of 2pi(7-x)(8-x^3) is (744pi)/5

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integral from 0 to 2 of 2pi(7-x)(8-x^3)

\int_{0}^{2} 2 π (7 - x) (8 - x^{3}) d x

\frac{744 π}{5}

Decimal

467.46898 \dots

Solution steps

\int_{0}^{2} 2 π (7 - x) (8 - x^{3}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 π \cdot \int_{0}^{2} (7 - x) (8 - x^{3}) d x

Expand

(7 - x) (8 - x^{3}) : 56 - 7 x^{3} - 8 x + x^{4}

= 2 π \cdot \int_{0}^{2} 56 - 7 x^{3} - 8 x + x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 π (\int_{0}^{2} 56 d x - \int_{0}^{2} 7 x^{3} d x - \int_{0}^{2} 8 x d x + \int_{0}^{2} x^{4} d x)

\int_{0}^{2} 56 d x = 112

\int_{0}^{2} 7 x^{3} d x = 28

\int_{0}^{2} 8 x d x = 16

\int_{0}^{2} x^{4} d x = \frac{32}{5}

= 2 π (112 - 28 - 16 + \frac{32}{5})

Simplify

2 π (112 - 28 - 16 + \frac{32}{5}) : \frac{744 π}{5}

= \frac{744 π}{5}

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What is the integral from 0 to 2 of 2pi(7-x)(8-x^3) ?
The integral from 0 to 2 of 2pi(7-x)(8-x^3) is (744pi)/5