What is the integral from 0 to 21pi of sin(x) ?

The integral from 0 to 21pi of sin(x) is 2

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integral from 0 to 21pi of sin(x)

\int_{0}^{21 π} sin (x) d x

2

Solution steps

\int_{0}^{21 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{21 π}

Compute the boundaries:

2

= 2

\int_{0}^{x^{2}} cos (x) d x

\int_{0}^{2 π} - 150 sin^{2} (t) d t

\int_{1}^{16} x^{- \frac{5}{4}} d x

\int_{0}^{1} 1 - x^{3} d x

\int_{x}^{π} \frac{sin ( y )}{y} d y

What is the integral from 0 to 21pi of sin(x) ?
The integral from 0 to 21pi of sin(x) is 2