What is the integral from 1 to 2 of x^{-5} ?

The integral from 1 to 2 of x^{-5} is 15/64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 2 of x^{-5}

\int_{1}^{2} x^{- 5} d x

\frac{15}{64}

Decimal

0.234375

Solution steps

\int_{1}^{2} x^{- 5} d x

Apply the Power Rule

= [- \frac{1}{4 x ^{4}}]_{1}^{2}

Compute the boundaries:

\frac{15}{64}

= \frac{15}{64}

\int_{4}^{5} \frac{x}{2 x - 6} d x

\int_{0}^{1} 5 x^{4} + 3 x^{2} + 1 d x

\int_{7}^{8} \frac{1}{x} d x

\int_{1}^{2} \frac{4 ( ln ( x ) ) ^{3}}{x} d x

\int_{0}^{4} (x - \frac{1}{2} x) d x

What is the integral from 1 to 2 of x^{-5} ?
The integral from 1 to 2 of x^{-5} is 15/64