What is the integral from 0 to 2pi of 32/3 ?

The integral from 0 to 2pi of 32/3 is (64pi)/3

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integral from 0 to 2pi of 32/3

\int_{0}^{2 π} \frac{32}{3} d θ

\frac{64 π}{3}

Decimal Notation

67.02064 \dots

Solution steps

\int_{0}^{2 π} \frac{32}{3} d θ

Integral of a constant:

\int a d x = a x

= [\frac{32}{3} θ]_{0}^{2 π}

Compute the boundaries:

\frac{64 π}{3}

= \frac{64 π}{3}

\int_{0}^{\frac{π}{4}} cos (x) sin (x) d x

\int_{0}^{7} x^{2} e^{- x} d x

\int_{- 1}^{1} r 1 - r^{2} d r

\int_{3}^{7} x^{2} d x

What is the integral from 0 to 2pi of 32/3 ?
The integral from 0 to 2pi of 32/3 is (64pi)/3