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Popular >

integral from-1 to 3 of |x|-1

Solution

\int_{- 1}^{3} ∣ x ∣ - 1 d x

Solution

1

Solution steps

\int_{- 1}^{3} ∣ x ∣ - 1 d x

Eliminate Absolutes

= \int_{- 1}^{0} - x - 1 d x + \int_{0}^{3} x - 1 d x

\int_{- 1}^{0} - x - 1 d x = - \frac{1}{2}

\int_{0}^{3} x - 1 d x = \frac{3}{2}

= - \frac{1}{2} + \frac{3}{2}

Simplify

- \frac{1}{2} + \frac{3}{2} : 1

= 1

Popular Examples

integral from 0 to 5 of 1/(sqrt(25-t^2))

\int_{0}^{5} \frac{1}{25 - t ^{2}} d t

integral from 1 to 3 of 1/(x^4)

\int_{1}^{3} \frac{1}{x ^{4}} d x

integral from 0 to 1 of sqrt(5x+6)

\int_{0}^{1} 5 x + 6 d x

integral from 1 to 4 of 2x^2

\int_{1}^{4} 2 x^{2} d x

integral from 0 to 8 of 8x

\int_{0}^{8} 8 x d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 3 of |x|-1 ?
The integral from-1 to 3 of |x|-1 is 1