What is the integral from 1 to 3 of 1/(x^4) ?

The integral from 1 to 3 of 1/(x^4) is 26/81

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integral from 1 to 3 of 1/(x^4)

\int_{1}^{3} \frac{1}{x ^{4}} d x

\frac{26}{81}

Decimal Notation

0.32098 \dots

Solution steps

\int_{1}^{3} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{1}^{3}

= [- \frac{1}{3 x ^{3}}]_{1}^{3}

Compute the boundaries:

\frac{26}{81}

= \frac{26}{81}

\int_{0}^{1} 5 x + 6 d x

\int_{1}^{4} 2 x^{2} d x

\int_{0}^{8} 8 x d x

\int_{0}^{3} 5^{3 x} d x

\int_{- 1}^{1} 2 x + 1 d x

What is the integral from 1 to 3 of 1/(x^4) ?
The integral from 1 to 3 of 1/(x^4) is 26/81