en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 2 of (2x+1)

Solution

\int_{- 1}^{2} (2 x + 1) d x

Solution

6

Solution steps

\int_{- 1}^{2} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 x d x + \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} 2 x d x = 3

\int_{- 1}^{2} 1 d x = 3

= 3 + 3

Simplify

= 6

Popular Examples

integral from 1 to 2 of ((x^2+4))/x

\int_{1}^{2} \frac{( x ^{2} + 4 )}{x} d x

integral from 1 to x of (e^t)/t

\int_{1}^{x} \frac{e ^{t}}{t} d t

integral from 0 to 1 of (1-x)^5

\int_{0}^{1} (1 - x)^{5} d x

integral from 0 to 1 of (1-y)^2

\int_{0}^{1} (1 - y)^{2} d y

integral from 0 to 2 of 10x

\int_{0}^{2} 10 x d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (2x+1) ?
The integral from-1 to 2 of (2x+1) is 6