What is the integral from 1 to 7 of (x^2-4x+4) ?

The integral from 1 to 7 of (x^2-4x+4) is 42

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 7 of (x^2-4x+4)

\int_{1}^{7} (x^{2} - 4 x + 4) d x

42

Solution steps

\int_{1}^{7} x^{2} - 4 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{7} x^{2} d x - \int_{1}^{7} 4 x d x + \int_{1}^{7} 4 d x

\int_{1}^{7} x^{2} d x = 114

\int_{1}^{7} 4 x d x = 96

\int_{1}^{7} 4 d x = 24

= 114 - 96 + 24

Simplify

= 42

\int_{0}^{2} x y^{2} d x

\int_{0}^{2} x \frac{3}{4} x (2 - x) d x

\int_{- 1}^{0} (6 x - 1) d x

\int_{0}^{\infty} \frac{x}{x ^{2} + 9} d x

\int_{2}^{x} x d x

What is the integral from 1 to 7 of (x^2-4x+4) ?
The integral from 1 to 7 of (x^2-4x+4) is 42