What is the integral from-(3pi)/4 to 0 of sin(x) ?

The integral from-(3pi)/4 to 0 of sin(x) is -1-1/(sqrt(2))

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integral from-(3pi)/4 to 0 of sin(x)

\int_{- \frac{3 π}{4}}^{0} sin (x) d x

- 1 - \frac{1}{2}

Decimal Notation

- 1.70710 \dots

Solution steps

\int_{- \frac{3 π}{4}}^{0} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- \frac{3 π}{4}}^{0}

Compute the boundaries:

- 1 - \frac{1}{2}

= - 1 - \frac{1}{2}

\int_{3}^{- 3} 9 - x^{2} d x

\int_{- 3}^{- 1} \frac{1}{x ^{2}} d x

\int_{0}^{4} y 9 + y^{2} d y

\int_{0}^{1} (x^{\frac{4}{3}} - 2 x^{\frac{1}{3}}) d x

\int_{1}^{6} ∣ 4 x - 12 ∣ d x

What is the integral from-(3pi)/4 to 0 of sin(x) ?
The integral from-(3pi)/4 to 0 of sin(x) is -1-1/(sqrt(2))