What is the integral from 0 to 4 of ysqrt(9+y^2) ?

The integral from 0 to 4 of ysqrt(9+y^2) is 98/3

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integral from 0 to 4 of ysqrt(9+y^2)

\int_{0}^{4} y 9 + y^{2} d y

\frac{98}{3}

Decimal Notation

32.66666 \dots

Solution steps

\int_{0}^{4} y 9 + y^{2} d y

Apply u-substitution

: \int_{3}^{5} u^{2} d u

= \int_{3}^{5} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{3}^{5}

= [\frac{u ^{3}}{3}]_{3}^{5}

Compute the boundaries:

\frac{98}{3}

= \frac{98}{3}

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What is the integral from 0 to 4 of ysqrt(9+y^2) ?
The integral from 0 to 4 of ysqrt(9+y^2) is 98/3