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Popular >

integral from 0 to 3 of-2y^2+6y

Solution

\int_{0}^{3} - 2 y^{2} + 6 y d y

Solution

9

Solution steps

\int_{0}^{3} - 2 y^{2} + 6 y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} 2 y^{2} d y + \int_{0}^{3} 6 y d y

\int_{0}^{3} 2 y^{2} d y = 18

\int_{0}^{3} 6 y d y = 27

= - 18 + 27

Simplify

= 9

Popular Examples

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\int_{0}^{2} \frac{2 x}{x ^{2} + 1} d x

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\int_{- 1}^{1} t^{3} (3 + t^{4})^{3} d t

integral from 0 to 2*pi of sin(x)

\int_{0}^{2 \cdot π} sin (x) d x

integral from 0 to 2pi of cos^2(v)

\int_{0}^{2 π} cos^{2} (v) d v

Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of-2y^2+6y ?
The integral from 0 to 3 of-2y^2+6y is 9