What is the integral from 0 to 9 of x^{1/2} ?

The integral from 0 to 9 of x^{1/2} is 18

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integral from 0 to 9 of x^{1/2}

\int_{0}^{9} x^{\frac{1}{2}} d x

18

Solution steps

\int_{0}^{9} x^{\frac{1}{2}} d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{9}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{9}

Compute the boundaries:

18

= 18

\int_{- 2}^{2} 2 x^{2} - 8 d x

\int_{2}^{3} x d x

\int_{0}^{1} \frac{x ( - x ^{2} + 1 ) ^{\frac{3}{2}}}{3} d x

\int_{- 1}^{1} x^{\frac{2}{3}} d x

\int_{\frac{π}{4}}^{\frac{π}{3}} csc^{2} (x) d x

What is the integral from 0 to 9 of x^{1/2} ?
The integral from 0 to 9 of x^{1/2} is 18