What is the integral from-1 to 1 of x^{2/3} ?

The integral from-1 to 1 of x^{2/3} is 6/5

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integral from-1 to 1 of x^{2/3}

\int_{- 1}^{1} x^{\frac{2}{3}} d x

\frac{6}{5}

Decimal

1.2

Solution steps

\int_{- 1}^{1} x^{\frac{2}{3}} d x

Apply the Power Rule

: [\frac{3}{5} x^{\frac{5}{3}}]_{- 1}^{1}

= [\frac{3}{5} x^{\frac{5}{3}}]_{- 1}^{1}

Compute the boundaries:

\frac{6}{5}

= \frac{6}{5}

\int_{\frac{π}{4}}^{\frac{π}{3}} csc^{2} (x) d x

\int_{0}^{π} t d t

\int_{\frac{π}{4}}^{\frac{π}{3}} tan^{2} (x) d x

\int_{0}^{3} (e^{x} + x) d x

\int_{1}^{2} \frac{3 x ^{2} - 1}{x ^{2}} d x

What is the integral from-1 to 1 of x^{2/3} ?
The integral from-1 to 1 of x^{2/3} is 6/5