What is the integral from 1 to 10 of c/(x^2) ?

The integral from 1 to 10 of c/(x^2) is (9c)/(10)

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integral from 1 to 10 of c/(x^2)

\int_{1}^{10} \frac{c}{x ^{2}} d x

\frac{9 c}{10}

Solution steps

\int_{1}^{10} \frac{c}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= c \cdot \int_{1}^{10} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{10}

= c [- \frac{1}{x}]_{1}^{10}

Compute the boundaries:

\frac{9}{10}

= c \frac{9}{10}

Simplify

= \frac{9 c}{10}

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What is the integral from 1 to 10 of c/(x^2) ?
The integral from 1 to 10 of c/(x^2) is (9c)/(10)