What is the integral from x^2 to x of 1 ?

The integral from x^2 to x of 1 is x-x^2

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integral from x^2 to x of 1

\int_{x^{2}}^{x} 1 d y

x - x^{2}

Solution steps

\int_{x^{2}}^{x} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x^{2}}^{x}

Simplify

= [y]_{x^{2}}^{x}

Compute the boundaries:

x - x^{2}

= x - x^{2}

\int_{- 1}^{1} x^{4} 1 - x^{2} d x

\int_{- 4}^{5} - x^{2} + x + 20 d x

\int_{4}^{6} x^{2} + 2 x - 2 d x

\int_{0}^{2} x^{4} - 8 x d x

\int_{0}^{1} 4 + 3 x^{2} d x

What is the integral from x^2 to x of 1 ?
The integral from x^2 to x of 1 is x-x^2