What is the integral from 0 to x of 3/x ?

The integral from 0 to x of 3/x is diverges

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integral from 0 to x of 3/x

\int_{0}^{x} \frac{3}{x} d x

diverges

Solution steps

\int_{0}^{x} \frac{3}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{x} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 3 [ln ∣ x ∣]_{0}^{x}

Compute the boundaries:

diverges

= diverges

\int_{0}^{2} \frac{2 x}{x ^{2} + 4} d x

\int_{0}^{5} \frac{1}{5 - x} d x

\int_{0}^{5} - x^{2} + 9 d x

\int_{0}^{b} \frac{1}{32} v e^{- \frac{v ^{2}}{64}} d v

\int_{0.25}^{4} \frac{1}{x} d x

What is the integral from 0 to x of 3/x ?
The integral from 0 to x of 3/x is diverges