What is the integral from 1 to infinity of 3x^{-3} ?

The integral from 1 to infinity of 3x^{-3} is 3/2

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integral from 1 to infinity of 3x^{-3}

\int_{1}^{\infty} 3 x^{- 3} d x

\frac{3}{2}

Solution steps

\int_{1}^{\infty} 3 x^{- 3} d x

Compute the indefinite integral:

\int 3 x^{- 3} d x = - \frac{3}{2 x ^{2}} + C

Compute the boundaries:

\int_{1}^{\infty} 3 x^{- 3} d x = 0 - (- \frac{3}{2})

= 0 - (- \frac{3}{2})

Simplify

= \frac{3}{2}

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What is the integral from 1 to infinity of 3x^{-3} ?
The integral from 1 to infinity of 3x^{-3} is 3/2