What is the integral from 0 to y of x^2 ?

The integral from 0 to y of x^2 is (y^3)/3

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integral from 0 to y of x^2

\int_{0}^{y} x^{2} d x

\frac{y ^{3}}{3}

Solution steps

\int_{0}^{y} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{y}

= [\frac{x ^{3}}{3}]_{0}^{y}

Compute the boundaries:

\frac{y ^{3}}{3}

= \frac{y ^{3}}{3}

\int_{1}^{4} (1 + \frac{1}{u} + \frac{1}{u ^{2}}) d u

\int_{1}^{0} x^{3} d x

\int_{0}^{2} 2 x x^{2} - 3 x + 2 d x

\int_{- 3}^{5} x^{2} d x

\int_{0}^{k} (2 k x - x^{2}) d x

What is the integral from 0 to y of x^2 ?
The integral from 0 to y of x^2 is (y^3)/3