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Popular >

integral from-1 to 1 of (x^2+x)

Solution

\int_{- 1}^{1} (x^{2} + x) d x

Solution

\frac{2}{3}

+1

Decimal Notation

0.66666 \dots

Solution steps

\int_{- 1}^{1} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} x d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} x d x = 0

= \frac{2}{3} + 0

Simplify

= \frac{2}{3}

Popular Examples

integral from 0 to 2 of x^2+5

\int_{0}^{2} x^{2} + 5 d x

integral from 0 to x/2 of cos(x)

\int_{0}^{\frac{x}{2}} cos (x) d x

integral from 0 to pi of (2x-sin(x))

\int_{0}^{π} (2 x - sin (x)) d x

integral from 0 to 9 of (9-x)

\int_{0}^{9} (9 - x) d x

integral from 0 to x^2 of xcos(y)

\int_{0}^{x^{2}} x cos (y) d y

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (x^2+x) ?
The integral from-1 to 1 of (x^2+x) is 2/3