What is the integral from 2 to 1 of x^3 ?

The integral from 2 to 1 of x^3 is -15/4

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integral from 2 to 1 of x^3

\int_{2}^{1} x^{3} d x

- \frac{15}{4}

Decimal

- 3.75

Solution steps

\int_{2}^{1} x^{3} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{2}

= - [\frac{x ^{4}}{4}]_{1}^{2}

Compute the boundaries:

\frac{15}{4}

= - \frac{15}{4}

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What is the integral from 2 to 1 of x^3 ?
The integral from 2 to 1 of x^3 is -15/4