What is the integral from 1 to 4 of 5x+sqrt(x) ?

The integral from 1 to 4 of 5x+sqrt(x) is 253/6

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integral from 1 to 4 of 5x+sqrt(x)

\int_{1}^{4} 5 x + x d x

\frac{253}{6}

Decimal

42.16666 \dots

Solution steps

\int_{1}^{4} 5 x + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 5 x d x + \int_{1}^{4} x d x

\int_{1}^{4} 5 x d x = \frac{75}{2}

\int_{1}^{4} x d x = \frac{14}{3}

= \frac{75}{2} + \frac{14}{3}

Simplify

\frac{75}{2} + \frac{14}{3} : \frac{253}{6}

= \frac{253}{6}

\int_{- \frac{π}{4}}^{\frac{π}{4}} (sec^{2} (x)) d x

\int_{0}^{1} e^{x^{3}} x^{2} d x

\int_{- 1}^{5} 2 x + 4 d x

\int_{0}^{1} x^{2} + x - 2 d x

\int_{0}^{x} \frac{t}{2} d t

What is the integral from 1 to 4 of 5x+sqrt(x) ?
The integral from 1 to 4 of 5x+sqrt(x) is 253/6