What is the integral from 2 to x of t^7 ?

The integral from 2 to x of t^7 is (x^8)/8-32

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integral from 2 to x of t^7

\int_{2}^{x} t^{7} d t

\frac{x ^{8}}{8} - 32

Solution steps

\int_{2}^{x} t^{7} d t

Apply the Power Rule

: [\frac{t ^{8}}{8}]_{2}^{x}

= [\frac{t ^{8}}{8}]_{2}^{x}

Compute the boundaries:

\frac{x ^{8}}{8} - 32

= \frac{x ^{8}}{8} - 32

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What is the integral from 2 to x of t^7 ?
The integral from 2 to x of t^7 is (x^8)/8-32