What is the integral from-1 to 14 of (sin(x))/x ?

The integral from-1 to 14 of (sin(x))/x is -\Si(-1)+\Si(14)

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integral from-1 to 14 of (sin(x))/x

\int_{- 1}^{14} \frac{sin ( x )}{x} d x

- Si (- 1) + Si (14)

Solution steps

\int_{- 1}^{14} \frac{sin ( x )}{x} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} \frac{sin ( x )}{x} d x + \int_{0}^{14} \frac{sin ( x )}{x} d x

\int_{- 1}^{0} \frac{sin ( x )}{x} d x = - Si (- 1)

\int_{0}^{14} \frac{sin ( x )}{x} d x = Si (14)

= - Si (- 1) + Si (14)

\int_{0}^{1} 80 x (2 x^{2} + 1)^{4} d x

\int_{- π}^{0} - cos (n x) d x

\int_{0}^{1} x e^{- s x} d x

\int_{0}^{1} ln (y) d y

\int_{0}^{- π} cos (x) d x

What is the integral from-1 to 14 of (sin(x))/x ?
The integral from-1 to 14 of (sin(x))/x is -\Si(-1)+\Si(14)