What is the integral from 10 to 20 of 3x^2+6x+300 ?

The integral from 10 to 20 of 3x^2+6x+300 is 10900

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integral from 10 to 20 of 3x^2+6x+300

\int_{10}^{20} 3 x^{2} + 6 x + 300 d x

10900

Solution steps

\int_{10}^{20} 3 x^{2} + 6 x + 300 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{10}^{20} 3 x^{2} d x + \int_{10}^{20} 6 x d x + \int_{10}^{20} 300 d x

\int_{10}^{20} 3 x^{2} d x = 7000

\int_{10}^{20} 6 x d x = 900

\int_{10}^{20} 300 d x = 3000

= 7000 + 900 + 3000

Simplify

= 10900

\int_{0}^{1} \frac{3}{8} x^{2} d x

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\int_{0}^{2} 1 + 4 t + t^{2} d t

\int_{- 1}^{x} \frac{3}{4} (1 - x^{2}) d x

\int_{1}^{5} e^{x} \cdot x^{2} d x

What is the integral from 10 to 20 of 3x^2+6x+300 ?
The integral from 10 to 20 of 3x^2+6x+300 is 10900