What is the integral from 0 to infinity of sin(t) ?

The integral from 0 to infinity of sin(t) is diverges

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integral from 0 to infinity of sin(t)

\int_{0}^{\infty} sin (t) d t

diverges

Solution steps

\int_{0}^{\infty} sin (t) d t

Compute the indefinite integral:

\int sin (t) d t = - cos (t) + C

Compute the boundaries:

\int_{0}^{\infty} sin (t) d t =

diverges

= diverges

\int_{0}^{2} 6 x^{3} d x

\int_{2}^{3} x^{2} - 2 x d x

\int_{- 2}^{2} - x d x

\int_{- 3}^{1} 3 - 2 x - x^{2} d x

\int_{2}^{4} ∣ x - 3 ∣ d x

What is the integral from 0 to infinity of sin(t) ?
The integral from 0 to infinity of sin(t) is diverges