What is the integral from 0 to 7 of kx ?

The integral from 0 to 7 of kx is (49k)/2

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integral from 0 to 7 of kx

\int_{0}^{7} k x d x

\frac{49 k}{2}

Solution steps

\int_{0}^{7} k x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{0}^{7} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{7}

= k [\frac{x ^{2}}{2}]_{0}^{7}

Compute the boundaries:

\frac{49}{2}

= k \frac{49}{2}

Simplify

= \frac{49 k}{2}

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What is the integral from 0 to 7 of kx ?
The integral from 0 to 7 of kx is (49k)/2