What is the integral from 1 to 3 of x^{-3} ?

The integral from 1 to 3 of x^{-3} is 4/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of x^{-3}

\int_{1}^{3} x^{- 3} d x

\frac{4}{9}

Decimal

0.44444 \dots

Solution steps

\int_{1}^{3} x^{- 3} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{3}

= [- \frac{1}{2 x ^{2}}]_{1}^{3}

Compute the boundaries:

\frac{4}{9}

= \frac{4}{9}

\int_{0}^{2} x^{2} 2 x - x^{2} d x

\int_{0}^{5} 8 e^{2 x} d x

\int_{x}^{2 x} e^{- t^{2}} d t

\int_{0}^{2} \frac{3 x}{( x + 1 ) ^{3}} d x

\int_{y}^{1} 2 d x

What is the integral from 1 to 3 of x^{-3} ?
The integral from 1 to 3 of x^{-3} is 4/9